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Python Input and Output Exercise: 20+ Coding Problems with Solutions

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Whether you’re building interactive command-line applications, processing data, or working with files, a solid understanding of Python’s input and output (I/O) mechanisms is crucial. At its core, input is how a program receives data, while output is how it presents results to the user.

This article is a practical guide to mastering these essential skills. This article provides 20+ Python Input and Output practice questions that focus entirely on taking user input, displaying information, and interacting with files. You will also learn techniques for formatting output to present your data clearly and in a user-friendly way.

Each coding challenge includes a Practice Problem, Hint, Solution code, and detailed Explanation, ensuring you don’t just copy code, but genuinely practice and understand how and why it works.

  • All solutions have been fully tested on Python 3.
  • Interactive Learning: Use our Online Code Editor to solve these exercises in real time.

Also Read:

+ Table of Contents (23 Exercises)

Table of contents

Exercise 1. Accept numbers from a user

Practice Problem: Write a program that accepts two integer numbers from the user and calculates their multiplication. Print the final result to the console.

Exercise Purpose: This exercise introduces the fundamental concept of user interaction. It teaches how to use the input() function to capture data and the importance of “type casting” (converting strings to integers) since all input starts as text.

Given Input:

  • First Number: 10
  • Second Number: 20

Expected Output: The multiplication is: 200

Help: Take user input in Python

Solution
# Accept input from user
num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))

# Calculate multiplication
res = num1 * num2

# Display result
print("The multiplication is:", res)Code language: Python (python)

Explanation to Solution:

  • int(input(...)): This nested function call takes the user’s keystrokes and immediately transforms them into a whole number (integer) so Python can do math with them.
  • num1 * num2: The asterisk is the multiplication operator in Python.
  • print(): This function outputs the final calculated value to the screen.

Exercise 2. Display variables with a separator

Practice Problem: Use the print() function to format the words “Name”, “Is”, and “James” so they appear with three asterisks (***) between them.

Exercise Purpose: The print() function is more powerful than it looks. This exercise teaches the use of the sep (separator) keyword argument, which allows you to define how multiple items should be joined together in the output without manually typing strings.

Given Input:

  • Strings: “Name”, “Is”, “James”

Expected Output:

Name***Is***James
Solution
# Using the sep parameter to join strings
print('Name', 'Is', 'James', sep='***')Code language: Python (python)

Explanation to Solution:

  • Comma Separation: In Python’s print(), commas signify different objects to be printed.
  • sep='***': By default, sep is a space. By changing it to '***', we tell Python to place that specific string between every object listed in the function call.

Exercise 3. Convert decimal number to octal

Practice Problem: Accept an integer from the user and display it as an octal number (Base 8).

Exercise Purpose: Computers often use different numbering systems (Hexadecimal, Octal, Binary). This exercise demonstrates how to use “Format Specifiers” in strings to automatically convert values between number systems for display.

Given Input: Decimal: 8

Expected Output:

The octal number of decimal number 8 is 10
Solution
num = 8
# Using %o to format the integer as octal
print('%o' % num)Code language: Python (python)

Explanation to Solution:

  • %o: This is a placeholder that tells Python: “Take the integer provided and represent it as an Octal value.”
  • Base-8 Logic: In Octal, the number 8 is represented as 10 because the system “rolls over” after 7.

Exercise 4. Binary representation

Practice Problem: Accept an integer from the user and display its value in binary format (Base 2).

Exercise Purpose: Computers process everything in binary. This exercise shows how to use Python’s built-in formatting to visualize how a decimal number is represented at the hardware level using only 0s and 1s.

Given Input: Decimal Number: 45

Expected Output:

The binary representation of 45 is 101101
Solution
num = int(input("Enter a decimal number: "))

# Using f-string with the 'b' (binary) type code
binary_val = f"{num:b}"

print(f"The binary representation of {num} is {binary_val}")Code language: Python (python)

Explanation to Solution:

  • :b: This is the binary type code. It tells Python to convert the integer into its Base-2 equivalent.
  • Base-2 Logic: In binary, 45 is calculated as ( 32 * 1 ) + ( 16 * 0 ) + ( 8 * 1 ) + ( 4 * 1 ) + ( 2 * 0) + ( 1 * 1)

Exercise 5. Accept any three strings from one input() call

Practice Problem: Write a program that takes three names (or any words) from a user in a single input prompt and assigns them to three separate variables.

Exercise Purpose: Users dislike having to hit Enter three times for three pieces of data. This exercise teaches the split() method, the standard way to parse a single string into multiple data points based on whitespace.

Given Input: Emma Jessa Kelly

Expected Output:

Name1: Emma
Name2: Jessa
Name3: Kelly
Solution
# Taking multiple inputs in one go
str1, str2, str3 = input("Enter three names: ").split()

print('Name1:', str1)
print('Name2:', str2)
print('Name3:', str3)Code language: Python (python)

Explanation to Solution:

  • .split(): By default, this function looks for spaces and “splits” the string there.
  • Unpacking: The syntax str1, str2, str3 = ... is called “iterable unpacking.” It takes the resulting list of three items and distributes them into the three variables in order.

Exercise 6. Hexadecimal representation

Practice Problem: Accept an integer and display its value in hexadecimal format (Base 16).

Exercise Purpose: Hexadecimal is widely used in computing for memory addresses and color codes (e.g., #FFFFFF). This exercise teaches you how to bridge the gap between human-readable decimals and developer-centric hex values.

Given Input: Decimal Number: 255

Expected Output: The hexadecimal value is ff

Solution
num = int(input("Enter a number: "))

# :x produces lowercase (ff), :X produces uppercase (FF)
hex_val = f"{num:x}"

print(f"The hexadecimal value is {hex_val}")Code language: Python (python)

Explanation to Solution:

  • :x: The hexadecimal type code. Hex uses sixteen symbols: 0–9 and a–f.
  • Case Sensitivity: Using lowercase x results in ff, while uppercase X would result in FF. This is a common requirement in protocol documentation.

Exercise 7. Display float number with 2 decimal places

Practice Problem: Display a float number (a number with decimals) such as 458.541315 rounded to exactly two decimal places.

Exercise Purpose: Real-world data can be messy. This task is important for UI/UX and reporting because it helps make long, complex floating-point numbers easier to read.

Given Input: Number: 458.541315

Expected Output: 458.54

Solution
num = 458.541315

# Displaying 2 decimal places using formatting
print('%.2f' % num)Code language: Python (python)

Explanation to Solution:

  • %.2f: The f stands for “float,” and the .2 tells Python to stop after two digits following the decimal point.
  • Rounding: Python automatically rounds the last digit appropriately when using this formatting method.

Exercise 8. Percentage display

Practice Problem: Ask the user for a numerator and a denominator. Calculate the percentage (numerator/denominator * 100) and display it with exactly two decimal places followed by a percent sign.

Exercise Purpose: In this exercise, you will learn about string interpolation. You will practice combining math results with symbols like % and learn how to control the number of decimal places so your answers look neat.

Given Input:

  • Numerator: 22
  • Denominator: 29

Expected Output: The result is: 75.86%

Solution
num = int(input("Enter numerator: "))
den = int(input("Enter denominator: "))

percentage = (num / den) * 100

# Using f-string for precision and adding the '%' literal
print(f"The result is: {percentage:.2f}%")Code language: Python (python)

Explanation to Solution:

  • percentage:.2f: Inside the curly braces of an f-string, the :.2f part tells Python to format the number as a float with two digits after the decimal point.
  • The trailing %: Since the percent sign isn’t a special character in f-strings (unlike in the old % formatting style), you can just type it at the end of the curly brace.

Exercise 9: Display right-aligned output

Practice Problem: Ask the user for a word and a number. Print the word right-aligned in a total field width of 20 characters, followed by the number.

Exercise Purpose: Good design is important. When you create text-based reports, lining up columns makes them easier to read. In this exercise, you will learn how to use Alignment Flags to set aside space on the screen and move text to the left, right, or center.

Given Input:

  • Word: “Python”
  • Number: 3.12

Expected Output:

               Python 3.14
Solution
word = input("Enter a word: ")
version = input("Enter a version number: ")

# Right-align the word in 20 spaces
print(f"{word:>20} {version}")Code language: Python (python)

Explanation to Solution:

  • :>20: This tells Python, “Reserve a block of 20 characters. Put the variable at the very end (right) and fill the remaining space on the left with blanks.”
  • Padding: If the word is “Python” (6 letters), Python will automatically insert 14 spaces before it.

Exercise 10. Center-aligned text

Practice Problem: Display a string centered within a 40-character field, using hyphens (-) as the padding character.

Exercise Purpose: Centering text is a common way to make headers or dividers in console reports. In this exercise, you will learn about the “Fill” and “Align” parts of f-string formatting.

Given Input: Text: “REPORT SUMMARY”

Expected Output:

-------------REPORT SUMMARY-------------
Solution
title = "REPORT SUMMARY"

# Center (^) with hyphen (-) as fill in a width of 40
formatted_title = f"{title:-^40}"

print(formatted_title)Code language: Python (python)

Explanation to Solution:

  • -: The character used to fill the empty space.
  • ^: The alignment flag for “Center.”
  • 40: The total width of the resulting string. Python calculates how many hyphens are needed on each side to make the total length exactly 40.

Exercise 11: Padding with zeros

Practice Problem: Ask the user for a number. Print this number padded with leading zeros so the total width is exactly 5 digits.

Exercise Purpose: This method is important when you need to create standardized IDs, serial numbers, or digital clock displays, such as showing “09” instead of “9” minutes. It shows you how to set a specific number format no matter the original input size.

Given Input: Number: 42

Expected Output: 00042

Solution
val = input("Enter your ID number: ")

# Method 1: Using zfill
print(val.zfill(5))

# Method 2: Using f-string (requires integer)
# print(f"{int(val):05}")Code language: Python (python)

Explanation to Solution:

  • zfill(5): This is a built-in string method specifically designed to add “0” characters to the start of a string until it reaches the desired length.
  • Use Case: This is incredibly common when naming files (e.g., image_001.jpg, image_002.jpg) so they sort correctly in your computer’s folders.

Exercise 12: Format variables using string.format() method

Practice Problem: Given three variables quantity = 3, totalMoney = 450, and price = 150, use the format() method to print a sentence that neatly displays these values.

Exercise Purpose: Hard-coding strings with plus signs (+) is messy and error-prone. This exercise introduces the .format() method, a powerful way to inject variables into templates with precision and readability.

Given Input: quantity = 3, totalMoney = 450, price = 150

Expected Output: 

I have 450 dollars so I can buy 3 football for 150.00 dollars.
Solution
quantity = 3
totalMoney = 450
price = 150
statement = "I have {1} dollars so I can buy {0} football for {2:.2f} dollars."

print(statement.format(quantity, totalMoney, price))Code language: Python (python)

Explanation to Solution:

  • {0}, {1}, {2}: These numbers refer to the position of the arguments in the .format() call. This allows you to reuse variables or change their order without rearranging the function call.
  • {2:.2f}: This is a bit of formatting magic that tells Python to treat the third variable as a float and show exactly two decimal places.

Exercise 13. Currency formatting with commas

Practice Problem: Display a large number as currency, including a dollar sign, commas for thousands, and two decimal places.

Exercise Purpose: Financial applications require strict formatting. This exercise combines three concepts: prefixing, grouping (using commas), and precision to create a professional-grade money display.

Given Input: Amount: 1250500.7

Expected Output: 

Total Balance: $1,250,500.70
Solution
balance = 1250500.7

# , adds commas, .2f adds two decimal places
formatted_balance = f"${balance:,.2f}"

print(f"Total Balance: {formatted_balance}")Code language: Python (python)

Explanation to Solution:

  • ,: This special grouping character tells Python to insert a comma every three digits.
  • .2f: Ensures the cents are always shown as two digits (e.g., .70 instead of .7).
  • $: Simply a literal character placed outside the curly braces to denote the currency.

Exercise 14: Accept a list of 5 float numbers

Practice Problem: Write a program that accepts 5 float numbers as input from the user and stores them in a list.

Exercise Purpose: This exercise moves beyond single variables to “Data Structures.” It teaches how to use loops or list comprehension to efficiently handle multiple inputs and store them in a single list.

Given Input: Numbers: 78.6, 78.6, 85.3, 1.2, 3.5

Expected Output: [78.6, 78.6, 85.3, 1.2, 3.5]

Refer: Take a list as input in Python.

Solution
numbers = []

# Run a loop 5 times to get 5 inputs
for i in range(0, 5):
    print("Enter number at location", i, ":")
    item = float(input())
    numbers.append(item)

print("User List:", numbers)Code language: Python (python)

Explanation to Solution:

  • numbers = []: Creates an empty container (list) to hold the data.
  • range(0, 5): Ensures the loop runs exactly five times.
  • float(input()): Similar to Exercise 1, but converts the input to a decimal-capable “float” instead of an integer.
  • .append(item): This method adds the new number to the end of the existing list.

Exercise 15. Tabular output from lists

Practice Problem: You have two lists: names = ["Alice", "Bob", "Charlie"] and scores = [85, 92, 78]. Print these as a table with aligned columns.

Exercise Purpose: This exercise introduces “Parallel Iteration.” It teaches you how to step through two related lists simultaneously and format them to look like an organized database table.

Given Input:

  • names = ["Alice", "Bob", "Charlie"]
  • scores = [85, 92, 78]

Expected Output:

Name       Score
----------------
Alice      85   
Bob        92   
Charlie    78
Solution
names = ["Alice", "Bob", "Charlie"]
scores = [85, 92, 78]

print(f"{'Name':<10} {'Score'}")
print("-" * 15)

for name, score in zip(names, scores):
    print(f"{name:<10} {score}")Code language: Python (python)

Explanation to Solution:

  • zip(names, scores): This “zips” the two lists together like a zipper, pairing “Alice” with 85, “Bob” with 92, and so on.
  • :<10: This is the “left-align” flag. It ensures the Name column is always 10 characters wide, so the Score column always starts at the exact same horizontal position.

Exercise 16. Interactive menu

Practice Problem: Create a menu that offers three options: “1. Say Hello”, “2. Calculate Square”, and “3. Exit”. The program should perform the action based on the number the user types.

Exercise Purpose: This is the foundation of “Command Line Interfaces” (CLI). It teaches you how to map user input to specific logic blocks using conditional statements, turning a linear script into an interactive application.

Given Input:

  • Choice: 2
  • Number to square: 5

Expected Output:

Enter choice (1-3): 2
Enter number to square: 5
The square is: 25
Solution
print("1. Say Hello\n2. Calculate Square\n3. Exit")
choice = input("Enter choice (1-3): ")

if choice == "1":
    print("Hello there! Hope you're having a great day.")
elif choice == "2":
    val = int(input("Enter number to square: "))
    print(f"The square is: {val * val}")
elif choice == "3":
    print("Exiting... Goodbye!")
else:
    print("Invalid choice. Please pick 1, 2, or 3.")Code language: Python (python)

Explanation to Solution:

  • String Comparison: Notice we compare choice == "1". Since input() returns a string, we don’t even need to convert it to an integer unless we plan to do math with the choice itself.
  • Control Flow: The elif (else-if) ensures that only one block of code runs, skipping the others once a match is found.

Exercise 17. Masked password input (getpass)

Practice Problem: Write a script that asks a user for their username using standard input and their password using masked input (where the characters don’t appear on the screen).

Exercise Purpose: Security is paramount. Using input() for passwords is a major vulnerability because the password remains visible in the terminal’s scrollback buffer. The getpass module is the standard way to handle sensitive credentials by suppressing local echo.

Given Input:

  • Username: admin
  • Password: SecretPassword123 (invisible during typing)

Expected Output:

Enter Username: admin
Password: 
Login successful for admin!
Solution
import getpass

user = input("Enter Username: ")
# Characters will not be displayed as you type
pwd = getpass.getpass("Password: ")

if user == "admin" and pwd == "SecretPassword123":
    print(f"Login successful for {user}!")
else:
    print("Access Denied.")Code language: Python (python)

Explanation to Solution:

  • import getpass: This is a standard Python library designed specifically for secure interaction.
  • getpass.getpass(): This function talks directly to the terminal to turn off “echoing.” While the user types, the cursor stays still, and no characters are sent to the display.
  • Logic: Despite being hidden from the screen, the variable pwd still stores the exact string the user typed for comparison.

Exercise 18. Read a file and store its content in a list

Practice Problem: Read an existing file test.txt and store every line as an individual element in a Python list.

Exercise Purpose: It’s the first step in “Data Parsing”, taking raw text from a disk and converting it into a structured format (a list) that Python can easily sort, filter, or search.

Given Input: A file test.txt with multiple lines.

Expected Output: ['Line 1', 'Line', 'Line']

See:

Solution
# Read file content into a list
with open("test.txt", "r") as f:
    lines = f.readlines()
    print(lines)Code language: Python (python)

Explanation to Solution:

  • readlines(): This is a memory-efficient way to capture the entire structure of a file.
  • \n in Output: You will notice the newline characters are preserved in the list. To remove them, you would typically use a list comprehension with .strip().

Exercise 19. Write list of strings to a file

Practice Problem: Take a list of favorite fruits and save each fruit onto a new line in a file named fruits.txt.

Exercise Purpose: In data science or web dev, you often process data in memory (as a list) and then need to “persist” it (save it to a disk). This exercise teaches you how to export structured Python data into a permanent text format.

Given Input:

  • fruit_list = ["Apple", "Banana", "Cherry", "Date"]

Expected Output: A file fruits.txt created with each fruit on its own line.

Help: Python write file

Solution
fruit_list = ["Apple", "Banana", "Cherry", "Date"]

# Open file for writing
with open("fruits.txt", "w") as f:
    for fruit in fruit_list:
        f.write(fruit + "\n")

print("File 'fruits.txt' has been created successfully.")Code language: Python (python)

Explanation to Solution:

  • with open(...) as f: This is the “Context Manager.” It handles opening and closing the file stream, ensuring no memory leaks occur even if the code fails midway.
  • "w" mode: This stands for “write.” Be careful: it will completely overwrite the file if it already exists.
  • + "\n": Files are just long streams of characters. We manually add the “New Line” character to ensure the file is human-readable.

Exercise 20. Count total lines in a file

Practice Problem: Write a program that opens an existing text file and calculates exactly how many lines of text it contains.

Exercise Purpose: This is a fundamental “Data Auditing” task. Before you process a log file or a dataset, you need to know its size. This exercise teaches you how to iterate through a file object efficiently.

Given Input: A file sample.txt with 12 lines of text.

Expected Output: 12

Solution
line_count = 0

with open("sample.txt", "r") as f:
    for line in f:
        line_count += 1

print(f"The file contains {line_count} lines.")Code language: Python (python)

Explanation to Solution:

  • Memory Efficiency: Instead of using f.readlines() (which loads the entire file into RAM), for line in f reads one line at a time. This allows you to count lines in a 10GB file without crashing your computer.
  • The Counter: Every time the loop completes one cycle, it means it found a newline character, so we increment line_count.

Exercise 21. Read line number 4 from a file

Practice Problem: Open a file and display only the fourth line of the content.

Exercise Purpose: Sometimes files are massive (gigabytes in size), and you only need a specific snippet. This exercise reinforces the idea that file lines can be treated like a list, allowing for direct, indexed access.

Given Input: A file test.txt containing:

Line 1
Line 2
Line 3
Line 4
Line 5

Expected Output: Line 4

See: Read Specific Lines From a File in Python

Solution
# Opening the file in read mode
with open("test.txt", "r") as f:
    # Read all lines into a list
    lines = f.readlines()
    # Print the 4th line (index 3)
    print(lines[3])Code language: Python (python)

Explanation to Solution:

  • readlines(): Once again, this creates a list where each element is one line of text.
  • lines[3]: Because Python is zero-indexed, the first line is at index 0, the second at index 1, and so on. Therefore, line 4 is found at index 3.

Exercise 22. Check if file is empty

Practice Problem: Write a script that checks a file’s metadata. If the file size is 0 bytes, print “File is empty”; otherwise, print the size in bytes.

Exercise Purpose: Sometimes a file exists but contains no data (common in failed downloads or interrupted logs). This exercise introduces the os module and “system metadata”—information about a file rather than the content inside it.

Given Input: An empty file named empty_log.txt.

Expected Output: 

Checking empty_log.txt...
Status: File is empty.
Solution
import os

filename = "empty_log.txt"

# Check if the file actually exists first to avoid errors
if os.path.exists(filename):
    file_info = os.stat(filename)
    if file_info.st_size == 0:
        print(f"Status: {filename} is empty.")
    else:
        print(f"Status: {filename} size is {file_info.st_size} bytes.")
else:
    print("File not found.")Code language: Python (python)

Explanation to Solution:

  • os.stat(): This function performs a “system call” to the Operating System to retrieve a structure of information (size, creation date, permissions).
  • .st_size: This specific attribute tells you the size in bytes. 1 byte usually equals one character.
  • os.path.exists(): A defensive programming practice that prevents your script from crashing if the file is missing.

Exercise 23. Delete a specific file

Practice Problem: Write a program that asks the user for a filename and deletes it from the folder. Caution: This operation is permanent.

Exercise Purpose: File system maintenance. This exercise shows you how Python can perform high-level administrative tasks. It also emphasizes the importance of “High Risk” operations and the need to always verify the user’s intent.

Given Input: Filename to delete: old_data.csv

Expected Output: 

Are you sure you want to delete 'old_data.csv'? (y/n): y
File 'old_data.csv' has been deleted.
Solution
import os

target = input("Enter filename to delete: ")

if os.path.exists(target):
    confirm = input(f"Are you sure you want to delete '{target}'? (y/n): ")
    if confirm.lower() == 'y':
        os.remove(target)
        print(f"File '{target}' has been deleted.")
    else:
        print("Operation cancelled.")
else:
    print("Error: File does not exist.")Code language: Python (python)

Explanation to Solution:

  • os.remove(): This is the core command that tells the OS to un-link the file from the directory. There is no “Recycle Bin” for this command; it is gone immediately.
  • .lower() == 'y': This makes your user interface more robust by accepting “Y” or “y”.
  • Defensive Logic: By checking os.path.exists(), you ensure the program handles missing files gracefully rather than stopping with a red error message.

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About Vishal

I’m Vishal Hule, the Founder of PYnative.com. As a Python developer, I enjoy assisting students, developers, and learners. Follow me on Twitter.

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Comments

  1. Malcolm says

    My answer for 6 removes the item from a list rather than skipping it during the write stage:

    old = open(‘test.txt’, ‘r’)
    document = old.readlines()
    old.close()
    document.pop(4)
    new = open(‘answer.txt’, ‘w’)
    for i in document:
    new.write(i)
    new.close()

    Reply

  2. Malcolm says

    An alternative for question 1:

    data = input(‘Enter two numbers separated by a space: ‘)
    a, b = data.split()
    print(‘{} times {} equals {}’.format(a, b, int(a)*int(b)))

    Reply

  3. sahul hameed says

    #exercise2
    class exercise2:
    def display(self):
    a=”Name”
    b=”Is”
    c=”James”
    print(a,b,c, sep=” **”)
    ex2=exercise2()
    ex2.display()

    Reply

  4. sahul hameed says

    #exercise 1
    class excercise1:
    def __init__(self):
    self.a=int(input(“enter the value for a”))
    self.b=int(input(“enter the value for b”))

    def calMulti(self):
    ans=self.a * self.b
    print(ans)

    ex1=excercise1()
    ex1.calMulti()

    Reply

  5. Adesayo says

    EXERCISE 5 SOLUTION

    numbers = []
    while True:
    item = (float(input(“enter a float”)))
    numbers.append(item)
    if len(numbers) == 5:
    break
    print (numbers)

    Reply

  6. Nethra says

    def exe_four():
    num = int(float(input(“Enter the number : “)))
    res = format(num, ‘.2f’)
    print(res)
    exe_four()

    //** I am not getting expected output **//

    Reply

  7. Phindulo Ratshilumela says

    Question 10

    with open(r”newone”,”r”) as file:
    lines = file.readlines()
    for i in range(len(lines)):
    if i == 3:
    print(lines[i])

    Reply

  8. Phindulo Ratshilumela says

    question 9
    we can use a list and check if the list is empty using the readlines
    with open(r”newone”,”r”) as file:
    lines = file.readlines()
    if lines == []:
    print(“there is nothing”)
    else:
    print(lines)

    Reply

  9. Phindulo Ratshilumela says

    Question 7

    user = input(“Enter three string: “).split(” “)
    count = 1
    for i in user:
    print(f”Name{count} : {i}”)
    count = count + 1

    Reply

    • Joonatan says

      names = input(“Enter three names separated by a space: “).split()
      for i, name in enumerate(names, 1):
      print(f”Name{i}: {name}”)

      Reply

  10. Phindulo Ratshilumela says

    Question 6

    with open(“small.txt”,”r+”) as file:
    altlist = []
    lines = file.readlines()
    for i in range(4):
    altlist.append(lines[i])
    print(altlist)
    newlines = lines[5:]
    print(newlines)
    newlist = altlist + newlines
    print(newlist)
    with open(“newone”,”w”) as newo:
    for line in newlist:
    newo.write(line)

    Reply

  12. ffrancisco says

    $exercise 1

    x = input(“1st number here “)
    y = input(“2nd number here “)

    z = (int(x)*int(y))

    print(z)

    Reply

  13. divya says

    q8:

    def formating(quantity,money,price):
    print(f"i have {money} so i can buy {quantity} football for {price:.2f}")
    formating(3,1000,450)

    with function

    Reply

  14. divya says

    question9:

    with open("empty.txt", "r") as file:
    content = file.read()

    if len(content.strip()) == 0:
    print("Empty")
    else:
    print("Not empty")

    we can aslo use tell() method to find the solution

    Reply

  15. Yutik says

    #6
    filename1 = "D:\\Exercise_python\\Doc1.txt"
    filename2 = "D:\\Exercise_python\\Doc2.txt"
    with open(filename1,'r') as file1:
    content = file1.readlines()
    with open(filename2,'w') as file2:
    for line in range(0,len(content)):
    if line == 4:
    continue
    file2.write(content[line])

    Reply

  17. 0xAH says

    #6

    with open('one.txt', 'r') as one:
    with open('two.txt', 'w') as two:
    x = 1
    for i in one:
    if x != 5:
    two.write(i)
    x += 1

    Reply

  19. Ankit Raj says

    QUES-8
    print("My name is {Myname},i'm {Age} old, my goal is to become {ds}".format(Myname="Ankit Raj",Age = 24, ds = "Data Scientist"))

    Reply

    • Atul Sachan says

      print("My name is {Myname},i’m {Age} old, my goal is to become {ds}".format(Myname="Ankit Raj",Age = 24, ds = "Data Scientist"))

      use the below instead if you are using python3.6 and above:
      These are called f strings. easy to use and comprehend.

      <codeMyname = 'Ankit Raj'
      Age = 24
      ds = 'Data Scientist'

      print(f'My name is {Myname}, I am {Age} years old and I want to become {ds}')

      Reply

  20. Abdallah Muhammad says

    QUESTION 5:
    numbers = [ ]
    for i in range(5):
    print('Enter a number at location', i, ":")
    number = float(input())

    numbers.append(number)
    print('Userlist:', numbers)

    Reply

  22. pratishtha Singh says

    question-5 Here is an alternative solution

    user_input=eval(input("Enter a list of five floating numbers: "))

convert_to_list=list(user_input)
print(convert_to_list)

output:  [78.6, 78.6, 85.3, 1.2, 3.5]
    Reply

    • Phindulo Ratshilumela says

      user = input(“Enter three string: “).split(” “)
      count = 1
      for i in user:
      print(f”Name{count} : {i}”)
      count = count + 1

      Reply

  24. Henry Piao says

    I have a problem while solving exercise 10. The Below code will not work properly but shows the wrong result.

    with open('./test.txt', 'r') as text:
    f_readline=text.readline(3)
    f_readlines=text.readlines()
    f_read=text.read()

    print(f_readlines[3])
    Reply

    • garoa says 

      with open('.//test.txt', 'r') as text:
      with open(r'./test.txt', 'r') as text:
      with open('.\test.txt', 'r') as text:

      / is escape character in python

      Reply

  25. Aravindan says

    1. Write a program to accept two numbers from the user and calculate multiplication

    user_a = int(input('enter your first number'))
user_ai = int(input('enter your second number'))

print(f'addition of {user_a} and {user_ai} is {user_a + user_ai}')
print(f'multiplication of {user_a} and {user_ai} is {user_a * user_ai}')

    2. 

    print('Name**name**Is**James')

    # or 

    print('My', 'Name', 'Is', 'James', sep='**')

    3. 

    num = 29
print('%o' % num) # % o - octal number base

    4. 

    num = 38.98989 

print('%.2f' %num)

    5. 

    a = []
for i,n in enumerate(range(5)):
    a.append(float(input(f'Enter the floating number:: {i}')))
print('Your Floating Values are')
print('')
print(a)

    6. 

    with open('test.txt', 'r') as read:
    li = read.readlines()  # Helps to read the lines!
    
with open('summa.txt', 'w') as read:
    for i,line in enumerate(li):
        if i == 4:
            i = 5
            continue # Here we are assigning i = 5 and skipping the 4 th index 
        else:
            read.write(line)   # Helps to write the lines

    7. 

    ie = input('Enter more names by using space in between!')

ie = ie.split()
print('\n')

for i in range(len(ie)):
    print(f'Name {i}: {ie[i]}')

    8. 

    import os # Operatung systms.. 
size = os.stat('test.txt').st_size 

if size == 0: # It means it does not have anything inside of this 
    print('file is empty')
else:
    print('file has something')

    9. 

    with open('test.txt', 'r') as file:
    li = file.readlines()
    
for i, r in enumerate(li):
    if i == 3:
        print(r)
    Reply

  27. Hemanta says 

    totalMoney = 1000
quantity = 3
price = 450
txt = "I have {} dollars so I can buy {} football for {} dollars."
print(txt.format(totalMoney,quantity,('%.2f' % price)))

    **You can do this way also**

    Reply

  28. amani says 

    count = 0
with open("test.txt", "r") as fp:
    lines = fp.readlines()
    count = len(lines)
with open("newFile.txt", "w") as fp:
    for line in lines:
        if (count == 3):
            count -= 1
            continue
        else:
            fp.write(line)
        count-=1

    i don’t understood it

    Reply

  29. WET says

    question 1 says to calculate multiplication but the given solution returns sum. also, it converts float inputs to int.

    Reply

  32. ilyass says

    i can do this just by this simple code :

    str = input('enter three strings : ')
print(str)

    output:

    Enter three strings : jhon emma kelly
jhon emma kelly
    Reply

    • John Smith says

      The exercise is asking for a specific output sequence that forces you to split the user input into three strings. There are many ways of accomplishing this. Here’s how I got there:

      user_input = input("Enter three string: ")
three_strings = user_input.split(" ")
id = 1
for name in three_strings:
    print(f"Name{id}: {name}")
    id += 1
      Reply

  33. Aman Pratap says

    Why this code is not working??
    Showing this error–

    Traceback (most recent call last):
    File “script.py”, line 5, in
    print(staa.format(mon, q, pr))
    ValueError: Format specifier missing precision

    
mon = 1000
q = 3
pr = 200
staa = "I have {0} money to buy {1} mangoes of price {2:.f} each"
print(staa.format(mon, q, pr))
    Reply

  34. Glückskeks says

    Can someone explain to me how the solution for exercise 4 works? I don’t know what ‘%o’ means.

    Reply

  35. Hung Phan says 

    
a = int(input ("your first number is: "))
b = int(input ("your second number is: "))

c = a*b
c = str(c)

print ("your result is: " + c)
    Reply

  36. Hung Phan says

    In Ex.1, it is stated that u have to calculate the multiplication of the 2 inputs rather than the sum of the two
    (as the result given has shown)

    
a = int(input ("your first number is = "))
b = int(input ("your second number is: "))

c = a*b
c = str(c)

print ("your result is: " + c)
    Reply

  37. Anchal says

    A person is playing a guessing game in which they have 3 guesses to figure out the computer’s secret letter which will be between A and Z inclusive. If they guess the letter correctly on the first guess the program should stop making them guess and they should get 26 points. If they guess the letter correctly on the second guess the program should stop making them guess and they should get 13 points. If they guess the letter correctly on the third guess, they should get 7 points. After an incorrect guess tell the user if their guess was too high or too low based on the results of checkGuess. If they fail to guess the letter correctly after 3 guesses they get 0 points. Be sure to tell them what score they got.

    Answer of this question how to make ipo chart

    Reply

    • John Smith says

      This was a fun exercise. Thank you! Here’s how I approached this challenge:

      import random, string

letters = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P',
'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
secret_letter = random.choice(letters)
p1, p2, p3, p4 = 26, 13, 7, 0

alphabet = dict()
for id, letter in enumerate(string.ascii_uppercase):
    alphabet[letter] = id + 1

rounds = 1
while rounds != 4:
    player_guess = input("Guess a letter from A - Z: ").upper()
    if rounds == 1 and player_guess == secret_letter:
        print(f"Congrats! You guessed the Secret Letter: '{secret_letter}' in Round {rounds}! You get {p1} points.")
        break
    elif rounds == 2 and player_guess == secret_letter:
        print(f"Congrats! You guessed the Secret Letter: '{secret_letter}' in Round {rounds}! You get {p2} points.")
        break
    elif rounds == 3 and player_guess == secret_letter:
        print(f"Congrats! You guessed the Secret Letter: '{secret_letter}' in Round {rounds}! You get {p3} points.")
        break
    elif rounds == 3 and player_guess != secret_letter:
        print(f"You failed to guess the secret letter, {secret_letter}, in time. You get {p4} points.")
        break
    else:
        if alphabet[player_guess]  alphabet[secret_letter]:
            print(f"Your guess, '{player_guess}' is too high.")

      rounds += 1

      Reply

  40. Michel says

    A simple solution for exercise 6 : )

    f0 = open('test.txt', 'r')

f = open('newTest.txt', 'w')

count = 0
for i in f0:
    if count != 5:
        f.write(i)
    count += 1

</pre?
    Reply

  41. zizzygirl says

    QUESTION8 

    totalMoney= 1000
quantity= 3
price= 450

    print(“I have {} dollars so I can buy {} football for {} dollars.”.format(1000, 3, 4500))

    Reply

      • Qudus says

        Better way to do exercise 5

        b = []
c = ['first', 'second', 'third','four','fifth']
for i in c:
	a = float(input(f'input {i} float: '))
	b.append(a)
print(b)
        Reply

  42. Chris says

    Vishal can you help, when I try to run the question 10 code it gives error saying I don’t have the file or directory.

    Reply

    • Abhijit says

      Hey Chris,

      Try to run it in your own IDE. First create a file with #text.txt on the same location where your python file is. Then run the code. Hope this helps!!!!!

      Reply

  43. Susmi Sharma says

    Easy way to do Exercise 5.

    
i = 0
Floatnumbers = []
while i != 5:
    ans = float(input("Enter a number:"))
    Floatnumbers.append(ans)
    i +=1
print(f"The User list is {Floatnumbers}.")
    Reply

  44. rahat says

    #question-6

    
with open("text.txt", "r") as f:
    lines = f.readlines()
count = 0
with open("newtext.txt", "w") as f:
    for i in lines:
        count+=1
        if count != 5:
            f.write(i)
    Reply

  45. Khalid says

    Question5:

    
list1 = [12, 15, 32, 42, 55, 75, 122, 132, 150, 180, 200]

for num in list1:
    if num <= 150 and num % 5 == 0:
        print(num)
    Reply

  46. code_teen says

    Easy solution for Question.5:

    
list1= []
for i in range(5):
    inputs = float(input())
    list1.append(inputs)
print(list1,end = ' ')

    Output:

    12.34
45.6
78.9
09.23
56.89
[12.34, 45.6, 78.9, 9.23, 56.89]
    Reply

  47. Khalid says

    Exercise 9

    
file_name ="C:/Users/RUFAI/Desktop/new file.txt"

with open(file_name) as file_object:
    content = file_object.read()
    if content == "":
        print("file is empty")
    Reply

  48. Khalid says

    Question6

    
with open("Test file.txt") as file_object:
    content = file_object.readlines()
count = 0
for lines in content:
    count += 1
    if count != 5:
        print(lines.strip())
        with open("new file.txt", 'a') as file_obj:
            file_obj.write(lines)
    Reply

  49. Khalid says

    Excersice 5

    
def enter_float_num():
    num_list = []
    print("Enter five float number at the prompt")
    while len(num_list) < 5:
        try:
            entry = float(input("Number entry: "))
            num_list.append(entry)
        except ValueError:
            print("Please enter a number")
    print(num_list)


enter_float_num()
    Reply

  50. Angshumaan Basumatary says

    Question 6: As I am a beginner I had gone through three different styles of for loops to keep track of indexing.
    For the beginner:
    1) Refer to the manual solution of sir which might make you more aware of how indexing works though it’s confusing for newbies.
    2) Try using range() if you have understood the first solution. (Check out my code below using a range)
    3) Try using enumerate() and is the easiest I have come across.
    …….Here is the code given below using range

    with open("test.txt", "r") as f:
    a = f.readlines()
with open("newFile.txt", "w+") as f:
    for line in range(0, len(a)):
        if line == 4:
            continue
        else:
            f.write(a[line])
    Reply

  51. Kid trying to learn Python says

    Hey Vishal, in the last ones, once I was done, I look at the solutions. I think you should do Variables and inputs, No DEF Functions. Thanks.

    Reply

  53. Kid trying to learn Python says

    What Does Exercise Question 8 mean, Mr. Vishal, or should I call You just Vishal.

    quantity = 3
totalMoney = 1000
price = 450

    Huh?

    Reply

    • Tousif says

      Q:display above data using string.format() method

      output : I have 1000 dollars so I can buy 3 football for 450.00 dollars

      Answer :
      totalMoney = 1000
      quantity = 3
      price = 450

      statement1 = “I have {1} dollar so I can buy {0} football for {2:.2f} dollars.”
      print(statement1.format(quantity, totalMoney, price))

      Reply

  54. Parag Khedikar says

    Solution 5 :

    def acceptfloatValue():
    lst = []
    for i in range(5):
        lst.append(float(input()))
    return lst

print('List is :',acceptfloatValue())

    
		
    

		
    Reply
    
		
	
    
	
    55. 

	
  55. 
	
    

		
		
    
			
    
				Parag K says			
    

			
    		
    

		
    
			
			
    Question 4:
    

    def add():
    a = float(input())
    b = float(input())
    return a+b


print("Values: ", add().__format__('.2f'))

    
		
    

		
    Reply
    
		
	
    
	
    56. 

	
  56. 
	
    

		
		
    
			
    
				Boris says			
    

			
    		
    

		
    
			
			
    Question 6, different way, without enumerate 
    

     text1=open("myfile.txt","r")
lines=text1.readlines()
del lines[4]
print(lines)
text2=(open("newfile.txt","w"))
for i in range(len(lines)):
 text2.write(str(lines[i]))
text2.close()
    
		
    

		
    Reply
    
		
	
    
	
    57. 

	
  57. 
	
    

		
		
    
			
    
				Nikhil K says			
    

			
    		
    

		
    
			
			
    For Q:6
    

    testFile = open("test.txt","r")
newFile = open("newFile.txt", "w+")

for num, line in enumerate(testFile, 1):
    if num == 5:
        continue
    else:
        newFile.write(line)


    
		
    

		
    Reply
    
		
	
    
	

    58. 

	
  58. 
	
	
    59. 

	
  59. 
	
    

		
		
    
			
    
				Yasin says			
    

			
    		
    

		
    
			
			
    For exercise 6, here is an alternative solution:
    

    testFile = open("test.txt","r")
newFile= open("newFile.txt", "w+")

for num, line in enumerate(testFile, 1):
    if num != 5:
        newFile.write(line)
  
    
		
    

		
    Reply
    
		
	
    
	

    60. 

	
  60. 
	
	
      

	
    • 
	
      

		
		
      
			
      
				Vishal says			
      

			
      		
      

		
      
			
			
      Hi Kevin, there is a small “upload button” on the right side of the text editor where you can upload your files. You need to import it in main.py to call its functions. Or if you have other files than .py just upload it and read it in main.py
      
		
      

		
      Reply
      
		
	
      
	
      • 

    

    61. 

	
  61. 
	
	

    62. 

	
  62. 
	
	
      

	
    • 
	
      

		
		
      
			
      
				Vishal says			
      

			
      		
      

		
      
			
			
      Hi, It is working on our end. You need to enter three strings separated by spaces when a program executes.
      
		
      

		
      Reply
      
		
	
      
	
      • 

    

    63. 

	

		
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